A, B and C use two ordinary cube dice to play the game, and agree that two dice with different points are used as the "lucky numbers" of the three people respectively, with A being 4, B being 5 and C being 9. Do you think this game is fair?

Solution: As shown in the figure:

- 1,2,3,4,5,6

1,2,3,4,5,6,7

2,3,4,5,6,7,8

3,4,5,6,7,8,9

4,5,6,7,8,9, 10

5,6,7,8,9, 10, 1 1

6,7,8,9, 10, 1 1, 12

As can be seen from the figure, "4" appears three times, "5" appears four times and "9" appears four times, and the probability of occurrence is112, 1/9 and 1/9 respectively, which is unfair to Party A. ..