1. Because ([UA] ∩ B = {2}, A ∩ ([UB) = {4},

Then 4 is in A, 2 is in B, and 4 and 2 are respectively substituted into the formula:

For A: 16+4p+ 12=0, then p=-7.

B: 4- 10+q=0, then q=6.

So p+q=- 1.

2. If x 2 -2 * x-8 = 0, then x=4 or -2.

And from a ∩ b = b, equation x? +ax+a？ -12 = 0 has three kinds of roots.

(1) If the root is 4 or -2, a =-2;

(2) If the equation has roots, then a = 4；;

(3) If the equation has no root, it can be obtained from the discriminant: a >；; 4 or a

To sum up, the range of A is: A.

3. Solution: [uA={ 1, 3,6,7}

[uB={2，4，6}

([uA]∩([uB]= { 6 }

([uA]∨([uB]= { 1，2，3，4，6，7}

[u(A∪B)={6}

[u(A∩B)={ 1，2，3，4，6，7}