Assuming that spiders, dragonflies and cicadas all have six legs, the total number of legs is 6× 16 = 96 (strips), which is less than the actual situation 1 10-96 = 14 (strips). This is because a spider has eight legs, so it counts as six legs, and each spider is less. Subtract 7 spiders from the total, and 16-7 = 9 (only) is the sum of dragonflies and cicadas. Assuming that all nine are dragonflies, the wings should be 2× 9 = 18 (right), that is, 18- 14 = 4 (right). This is because cicadas have 1 pair of wings, so they are counted as two pairs, and each cicada has 1 pair of wings. Found cicadas and dragonflies can be found.

Solution: (110-6×16) ÷ (8-6) =14 ÷ 2 = 7 (only)-Spider.

16-7 = 9 (only)

(2× 9-14) ÷ (2-1) = 4 ÷1= 4 (only)-cicada

9-4 = 5 (only)-Dragonfly

A: There are 7 spiders, 5 dragonflies and 4 cicadas.