Mathematical problems about calendars
1, let Monday be a, then Tuesday is A+ 1, then Sunday is A+6, a+(a+1)+(a = 242) ...+(a+6) = 7a+(1+2. The minimum number is 143, and if the minimum number is a, we can know that the remaining six numbers are: A+2, A+4, A+6, A+8, A+ 10, a+12/kloc-6. Calculate A= 174, and these four numbers are 3, 4, 10,1. Sum of squares = 9+16+100+121= 20.