2.( 1) With A as the abscissa and B as the ordinate, the values of A and B are respectively (1, 1), (-1, 1), (1,/kloc-0. If two of +ax+b = 0 are real numbers, then a? The point of -4b ≥ 0 is a parabola b = 1/4a? The area enclosed by the square below can be calculated as 13/6 through integration, so the probability is 13/6 ÷ 4 = 13/24.
(2) imitate the above. At this time, A and B should not only satisfy A, right? -4b ≥ 0, and a < 0, b > 0 must be satisfied, so that a and b that meet the conditions fall on the parabola b = 1/4a? In the second quadrant, the lower area surrounded by the X axis and the straight line X =- 1 can be obtained as 1/6 through integration, so the probability is 1/6 ÷ 4 = 1/24.