The question about 1 2 is simple. Anyone who has studied solid geometry in middle school can give an answer at once. I think you can do it, so I won't say much. Talk about the problem of coordinate rotation.

The problem of rotating a point (x, y, z) in the coordinate system is a linear transformation.

That is to say, a matrix T maps points (x, y, z) to new coordinates (x', y', z') through T*(x, y, z).

The transformation matrix t about clockwise rotation of y axis 1 degree is

[cos(a) 0 sin(a) ]

[0 1 0 ]

[sin(a) 0 cos(a) ]

So t * (x, y, z) = (cos (a) x+sin (a) z, y, sin (a) x+cos (a) z)

For example, if a = 30, COS (a) = √ 3/2, and SIN (a) = 0.5.

Then the result of rotating point A (1, 1) clockwise by 30 degrees on the Y axis is (√ 3+1)/2, 1, (√ 3+ 1)/2). Other points can be calculated according to this method and formula.

The matrix T = rotates clockwise about the x axis by one degree.

[ 1 0 0 ]

[0 cos(a) sin(a) ]

[0 -sin(a) cos(a) ]

That is t * (x, y, z) = (x, cos (a) y+sin (a) z, -sin (a) y+cos (a) z)

Also follow the previous method and formula.