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Senior three rounds of math series review homework! ! ! This is urgent.
an=a^(n- 1)+a^n+……+a^(2n-2)

( 1) a=0 Sn= 1

(2) a= 1

an=n Sn=n( 1+n)/2

(3)a≠0, 1

an=a^(n- 1)*( 1-a^n)/( 1-a)=(a^(2n- 1)-a^(n- 1))/(a- 1)

sn=[(a^ 1+a^3+a^5+……+a^(2n- 1))-( 1+a+a^2+a^3+……+a^(n- 1))]/(a- 1)

=[a( 1-a^2n)/( 1-a^2)-( 1-a^n)/( 1-a)]/(a- 1)

=[a^(2n+ 1)-a^n-a^(n- 1)+ 1]/[( 1-a^2)( 1-a)]