The distance of MF 1 is 5/3, and you can find the left mark of m (-2*√6).

/3,

2/3)

Then the ellipse passes through m points, and then its equation can be solved by combining the focal coordinates.

a=2

b=√3

2. Divide the polygon into two triangles, AEF and BEF, and you can find the distance from point A and point B to the straight line, that is, the height of the two triangles, which are k*√3/

(√k^2+ 1)

and

2/

(√k^2+ 1)

K can also be used to represent the length of EF straight line, which is 4 * (√ 3k2+3).

/

(√ 3k 2+4), then the area of the polygon is represented by k, and the maximum value can be obtained.