Solution:

The answer is c,

When the two ends of the line segment coincide with the whole point, it covers 2008 points; When both ends are not on the hour, cover 2007 points.

For example, a line segment with length 3, when the starting point of the line segment is 1.5.

Then the ending is 4.5, covering 3 whole points.

18.

Solution:

( 1)

According to the known conditions, the coordinate of point B minus the coordinate of point A is the distance of AB, then

AB= 14-(-6)=20

By AC:BC= 1:5, then

AC=20*( 1/6)=4

BC=20

So the coordinates of point C are the coordinates of point A plus 4, so the corresponding number of point C is-10+4=-6.

(2)

First, two cases are distinguished: two units from the origin can be point -2 or point 2.

Suppose we meet at point 2, then at the same time, A turns left 10+2= 12.

B gone: 14-2= 12.

Therefore, according to this assumption, the speed of deducing A and B is equal, which is inconsistent with what is known, so the assumption does not hold.

So, the meeting place is -2. At this time, A left 8, B left 16.

Let the speed of A be x, then the speed of B is x+3.

According to the time it takes two people to meet, according to the distance divided by the speed is equal to the available time.

8/x= 16/(x+3)

solve

x=3

The speed of armor is 3.

B's speed is 6.

(3) According to Condition 2, then

The speed of A is 3, and the speed of B is 6.

Both Party A and Party B walked to the left, so when they met again, Party A walked 20 more than Party B..

Suppose the meeting time is t, then there is

6t-20=3t

solve

t=20/3

At this time, a left hand.

3*20/3=20

So the coordinate of the intersection is a, and the coordinate moves 20 units to the left, which is -30.