set up

melon farmer

* * * Send them X.

watermelon

Eight quit to get y.

10 & lt； X & lt20, X and Y are

positive integer

y+y/2+y/3+ 1=x

10 & lt； 1 1y/6+ 1 & lt； 20

54/ 1 1 & lt； y & lt 1 14/ 1 1

5 & lt= y & lt= 10

Y is 2, 3

multiple

, so y=6

The melon farmers * * * gave them11* 6/6+1=12 watermelons.

set up

Bajie watermelon

The number x,

rule

The total number of watermelons donated by melon farmers is:

1+x+( 1/2)x+( 1/3)x = 10 ~ 19。

Trial and error method, x must be divisible by 2 and 3 (that is, divisible by 6) and satisfy the above formula, so

X can be 6, 12, 18 and so on.

compound

Title meaning

When x=6, the total number of watermelons given by melon farmers is (1+6+3+2)= 12.

This fits the problem, so

The total number of watermelons donated by melon farmers is

12

I think so! Thank you! ! !