1(1+6) =1/7.

1- 1/7=6/7 of the total number of people who passed the exam.

So the first scene,

There are 2 more failures than the total 1/7.

Two people passed, less than 6/7 of the total.

I also know that in the first game,

Two people passed four times more than those who failed.

That is, there are two more people than the total number 1/7×4=4/7 plus 2×4=8.

That is, 8+2= 10 people exceed 4/7 of the total.

So this is an equal relationship:

6/7 of the total minus 2 people equals 4/7 of the total plus 10 people.

Total population: (10+2)÷(6/7-4/7)=42.

Another solution:

In the second game, the number of people who passed was six times that of those who failed.

Compared with the second game, two more people failed in the first game.

If passed, increment: 6×2= 12 persons.

So those who pass the exam are still six times more likely to fail than others.

In fact, the number of people who passed did not increase by 12, but decreased by 2.

Poor: 12+2= 14 people.

At this time, two people passed the exam, four times more than those who failed.

So, in the first scene,

Four times as many people as two fail, and 14 is less than six times as many people fail.

Number of failures: (2+ 14)÷(6-4)=8.

Qualified personnel: 8×4+2=34.

Total: 8+34=42.