Drawing this problem will be relatively simple, but drawing should be standardized: take any point P on AB as PE 1, PE2 passes through point P, perpendicular to AB, PE 1, PE2, all of which are 1, and make straight lines L 1, L2 and E2 pass through E/kloc-. The distance from any point on L2 to AB is 1. Similarly, if L3 and L4 are parallel to AC, the distance from any point on L3 and L4 to AC will be 2. If L 1, L2, L3 and L4 are extended, they can intersect at four points, which means that these four points are all points with distances to AB and AC of 1 and 2 respectively. Of the four points, the nearest point is 1 and the farthest point is 7.

Of course, it can also be calculated, but the quantity is faster and simpler. Hope to adopt.