And the absolute value of the abscissa of each point in each period is higher than the absolute value of the abscissa of the corresponding point in the period by 1 unit; The ordinate value of each point is greater than the ordinate value of the period by 2.

Let each issue be grouped according to point P 1P2P3P4.

The coordinates of the first periodic point P 1P2P3P4 are (1, 1) (- 1, 1) (- 1, 2) (2,2).

The coordinates of the second periodic point P 1P2P3P4 are (2,3) (-2,3) (-2,4) (3,4).

......

The coordinate of the nth periodic point P 1P2P3P4 is (n, 2n- 1) (-n, 2n- 1) (-n, 2n) (n+ 1, 2n).

Analysis of 50÷4= 12+2

P50 is located in 13 transportation cycle, which is the second point of this cycle.

Substitute into the periodic general term formula

Know the abscissa of P50-13 and the ordinate of 2× 13- 1=25.

That is, point P jumps from 50th to p50 coordinate (-13,25).