And the absolute value of the abscissa of each point in each period is higher than the absolute value of the abscissa of the corresponding point in the period by 1 unit; The ordinate value of each point is greater than the ordinate value of the period by 2.
Let each issue be grouped according to point P 1P2P3P4.
The coordinates of the first periodic point P 1P2P3P4 are (1, 1) (- 1, 1) (- 1, 2) (2,2).
The coordinates of the second periodic point P 1P2P3P4 are (2,3) (-2,3) (-2,4) (3,4).
......
The coordinate of the nth periodic point P 1P2P3P4 is (n, 2n- 1) (-n, 2n- 1) (-n, 2n) (n+ 1, 2n).
Analysis of 50÷4= 12+2
P50 is located in 13 transportation cycle, which is the second point of this cycle.
Substitute into the periodic general term formula
Know the abscissa of P50-13 and the ordinate of 2× 13- 1=25.
That is, point P jumps from 50th to p50 coordinate (-13,25).