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Mathematical olympiad geometry problems in the first day of junior high school
Point p has 4 graphic cycles per hop.

And the absolute value of the abscissa of each point in each period is higher than the absolute value of the abscissa of the corresponding point in the period by 1 unit; The ordinate value of each point is greater than the ordinate value of the period by 2.

Let each issue be grouped according to point P 1P2P3P4.

The coordinates of the first periodic point P 1P2P3P4 are (1, 1) (- 1, 1) (- 1, 2) (2,2).

The coordinates of the second periodic point P 1P2P3P4 are (2,3) (-2,3) (-2,4) (3,4).

......

The coordinate of the nth periodic point P 1P2P3P4 is (n, 2n- 1) (-n, 2n- 1) (-n, 2n) (n+ 1, 2n).

Analysis of 50÷4= 12+2

P50 is located in 13 transportation cycle, which is the second point of this cycle.

Substitute into the periodic general term formula

Know the abscissa of P50-13 and the ordinate of 2× 13- 1=25.

That is, point P jumps from 50th to p50 coordinate (-13,25).