The train from A to B has a speed of 48 kilometers per hour and arrives at noon 12. 80 kilometers per hour, 10 am arrived. If it is to arrive at 1 1 am, what is the speed of this train?

The train travels at a speed of 48 kilometers per hour, and it takes X hours to reach the second place.

Then the distance between Party A and Party B is 48x, and driving at 80km/h needs 48x/80.

x-(48x/80)= 12- 10

0.4x=2，x=5

48×5=240 km

240÷ (5-(12-11)) = 60 (km/h)

A: If we want to arrive at 1 1 in the morning, the speed of this train is 60 kilometers per hour.