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The second math problem
Solution: Let DP=x, then AP=7-x, and CE∨AD and AB are in E, ∫AB∨CD, ∠A=90? ,∴∠D=90? ∴∠AEC=90?

∴ Quadrilateral AECD is rectangular, CE=AD=7, AE=CD=2, BE=AB-AE= 1.

∴BC? = Yes? +CE? = 1+49=50

CP? =CD? +DP? =4+x?

BP? =AP? +AB? =(7-x)? +9

∵CP? +BP? =BC? ,∴4+x? +(7-x)? +9=50

Tidy up, x? -7x+6=0, solution, x= 1 or x=6.

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