Solution: We go to the swimming pool for X times, and pay Y 1 yuan with membership card, and Y2 without coupons, so Y 1=80+X, Y2=3X.
Solution: Go to the swimming pool X times and pay the same money as if you had a membership card.
Equation 80+x=3x can be listed.
Find x=40.
So going to the swimming pool 40 times with a membership card is the same as not having a membership card.
Then it is more cost-effective to apply for a membership card for more than 40 times than not to apply for a membership card.
Then it is more cost-effective not to apply for a membership card within 40 times than to apply for a membership card.
2. Solution: After setting X minutes, the hour hand and minute hand of the clock coincide.
List the equation x/60*360=x/60*30+90.
X= 180/ 1 1 min.
After setting y minutes, the hour hand and minute hand of the clock form a right angle.
List the equation y/60*360- 180=y/60*30+90.
The solution is y=540/ 1 1 min.
Z minutes later, the hour hand of the clock is at right angles to the minute hand.
List the equation z/60*360-90=z/60*30+90.
The solution is z=360/ 1 1 min.