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Solve three problems in the second grade mathematics "Classroom Perception in Training"! ~(& gt; _ & lt)~ Please
1. Because d is the midpoint of the BC side,

So BD=CD

DE⊥AB,DF⊥AC,DE=DF,

So△ bed congruence △CFD(HL)

So ∠B=∠D

So AB=AC

2. Because BD⊥AC is in D, CE⊥AB is in E, BD=CE, BC=BC.

So △BEC congruence△ △CDB(HL)

So ∠ABC=∠ACB

So △ABC says isosceles triangle

3.OE vertically divides AB

Because AB=BA, ∠BAC=∠ABD, AC=BD,

So △DAB congruence△ △CBA(SAS)

So ∠DAB=∠CBA

Point e is the midpoint of AB,

So OE bisects AB vertically (isosceles triangle with three lines combined into one)