Solution: (1) From the meaning of the question: A (0 0,8), B (-3,0)

And s quadrilateral OEDA= 10, h=OA=8.

So BE=2.5

I.e. 2.5 units to the right.

(2)FO=BE=2.5

Then BF=2.5+3=5.5.

When two points intersect, t = 5.5/(1+2) =11/6.

That is, when 0 is less than t and less than 1 1/6, s =1/2 * (5.5-3t) * 8 = 22-12t.

When t= 1 1/6, S= 1/2*0*8=0.

When t is greater than 1 1/6, s =-1/2 * (5.5-3t) * 8 =12t-22.