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The topic in the special training of junior high school mathematics synchronous class! !
1, "The abscissa of the vertex is twice the ordinate and twice the axis of symmetry" Don't you understand that the abscissa of the vertex should not be the value of the axis of symmetry?

2、

Solution: A (-b/2a,0) means A (-2c,0) A(-2c (0,c).

The distance between two points A and B is 2.

∴(-2c-0)? +(c-0)? =(2 root numbers 2)?

Solution: c = 2 * (root number 10)/5

Vertex a is on the x axis.

The quadratic function ∴ has only one intersection with the z axis.

Discriminant b? -4ac=0

∫b = 2ac

∴4a? c? -4ac=0

∵a≠0,c≠0

∴ac= 1

∴ The analytic formula of quadratic function is y=[ (root number 10)/4]x? +x+2* (root number 10)/5

Or y=-[ (root number 10)/4]x? +x-2* (root number 10)/5

3. Solution:

Angle ACB=90 degrees

∴C is on a circle with a diameter of AB.

The maximum value of this function is equal to 2.

The radius of a circle is 2.

∴ The diameter is 4, which means AB=4.

The abscissa of point A is 1.

The abscissa of point B is 5 or -3.

The abscissa of point C is half of the sum of the abscissas of ab.

That is, the abscissa of point C is 3 or-1.

∴ get:

A( 1,0) B(5,0) C(3,2)

Or a (1, 0) b (-3, 0) c (- 1, 2)

Two situations

Solve the resolution function as follows:

y=-x? /2+3x-5/2 or y=-x? /2-x+3/2