The original surface area of a cuboid is (5*3+5*4+3*4)*2.
So the surface area of two cuboids is (5*3+5*4+3*4)*2*2.
When the reduced surface is the smallest, the surface area is the largest; (The area of 3*4 faces is the smallest, reducing two faces)
When the converted surface area is the largest, the surface area is the smallest; (The area of 5*4 faces is the largest, and two faces are reduced)
So the maximum value is: (5 * 3+5 * 4+3 * 4) * 2 * 2-3 * 4 * 2 =188-24 =164 (square centimeter).
The minimum is: (5 * 3+5 * 4+3 * 4) * 2 * 2-5 * 4 * 2 =188-40 =148 (square centimeter).
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