The probability that the computer will not make mistakes is: (1- 10-6) 3, and the value is x.

The probability of one and only one fault is 3 (10-6) (1-10-6) 2, and the value is set to y.

Then, the probability of the rocket running correctly is x+y = (1+2 *10-6) (1-kloc-0/0-6) 2. Sorry, there is no calculator. You can do it yourself.

There are ten situations in the competition * * *:

M won the first and second sets;

E won the first set and the second set;

M won the first set, and E won the second and third sets.

E won the first set, and M won the second and third sets.

M won the first, third and fourth sets, and E won the second set;

E won the first, third and fourth sets, and M won the first ear;

M won the first, third and fifth sets, and E won the second and fourth sets.

E won the first, third and fifth sets, and M won the second and fourth sets;

M won the second, fourth and fifth sets, and E won the first and third sets.

E won the second, fourth and fifth sets, and M won the first and third sets.