∴AE∥BC，

∴△BPC∽△EPA，

AB = 8，BC=6，

∴AC= 10，

* APCP = AECB，

That is AP 10-AP= 156.

Solution: AP=507 ..

(2)∫AB = 8，AE= 15，

∴BE= 17.

For AH⊥BE, the vertical foot is h,

Then AB? AE=BE？ Ah,

∴AH=AB？ AEBE = 8× 15 17 = 120 17。

∵507> 120 17,

∴⊙A and Britain intersect.

(3) As shown in the figure, point D is inside the moving ⊙A, and point B is outside the moving ⊙A,

The radius of motion circle a is 6 < r 1 < 8.