After reading the question, I noticed that the time for a dog to go (56+ 1 12) meters from A to C is t, which is the same as the time for a rabbit to go 1 12 meters from B to C.
Because "the dog jumps 2 meters at a time", during this period, the dog jumps (56+ 1 12)/2=84 times.
Because the time for a dog to jump three times is the same as that for a rabbit to jump four times, we can calculate the time for a dog to jump one time, and the rabbit can jump four-thirds. Therefore, for a dog to jump 84 times, the rabbit can jump 84 * (4/3) =12 times, and the rabbit will arrive at C from B and go forward1/kloc.