Solution: let the first group produce X. ..
2/3-500+X+5/6+200 = 6000
X= 1890
1890× 5/6+200 =1775 (pieces)
A: The third group produced 1775.
A barrel of oil in the canteen is 58 kilograms, and it will be used up in three days. On the first day, 1/3 was used, on the second day, the remaining 2/3 was used, and on the third day, it was 6 kg less than the sum of 3/7 used in the previous two days. How many kilograms does this bucket weigh?
Solution: let the oil weigh x kilograms.
x- 1/3x-2/3 * 2 * 3x-( 1/3x+2/3 * 2/3x)* 3/7+6 = 0
x=54
58-54=4 kg
Method 2:. Solution: let the first group produce X. ..
2/3-500+X+5/6+200 = 6000
X= 1890
1890× 5/6+200 =1775 (pieces)
Suppose the oil weighs y kilograms.
y- 1/3Y-2/3 * 2 * 3Y-( 1/3Y+2/3 * 2/3Y)* 3/7+6 = 0
Y=54
58-54=4 kg