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Beijing Normal University mathematics P39 ninth gradeNo. 10 gold medal learning code
It is proved that ∵ quadrilateral ABCD is a parallelogram (known),

∴AD‖BC, AB=CD (the opposite sides of a parallelogram are parallel and equal)

∴∠GBC=∠BGA, ∠BCE=∠CED (two straight lines are parallel with equal internal angles).

There are also ∵BG bisection ∠ABC, CE bisection ∠BCD (known),

∴∠ABG=∠GBC, ∠BCE=∠ECD (definition of angular bisector)

∴∠ABG=∠GBA,∠ECD=∠CED.

∴AB=AG, CE=DE (in the same triangle, equilateral)

∴AG=DE,

∴AG-EG=DE-EG, namely AE = DG.