Let h(x)=f(x)+x? , then h(x)+h(-x)=0 (odd function)

So 0 = h (1)+h (-1) = f (1)+1+f (-1)+1= f (1)

Because f( 1)= 1.

So f(- 1) = -3.

Because g(x) = f(x)+2.

So g (-1) = f (-1)+2 =-1.