Solution: rotate Δ δDBC 60 counterclockwise around point D? , get delta deltaδDAE, connect EC, and then
CD = ED and ∠EDC = 60?
∴δedc is an equilateral triangle, and EC = CD.
And AE = BC, therefore, from EC≤AE+AC, we know that CD ≤ A+B.
If and only if the lines C, A and E***, the equal sign holds, CD is the largest.
At this time ∠DCB =∠DEC =∠DCE = 60? , and ∠ACB =∠DCB+∠DCE.
∴∠ACB = 120? , CD is the largest, and the maximum value is a+B.
For reference only.