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Choose 2-3 math problems in Senior Two.
First of all, there are two situations.

1, invest in two projects in one city and invest in 1 project in another city.

Divide the project into 2 and 1, and there are 3 kinds;

Among the four cities, two cities are selected as investment targets, with 4 * 3 = 12.

This situation is: 3× 12=36 species.

2. Three cities each get an investment project.

Choose four cities that have not obtained investment projects;

There are 3 * 2 * 1 = 6 projects in the corresponding city.

There are 4×6=24 kinds of this situation.

Based on these two situations, there are 36+24 = 60 investment projects.