Seven people in a row. Party A and Party B must be adjacent, but Party B cannot be adjacent. There are several arrangements. The answer is 960.

A:

The first one: consider A and B as one copy, except for D, there are four copies, and the whole arrangement is 4, 24.

There are two arrangements, A and B, 2

The arrangement of four copies just now, except for the space between A and B, is still four copies, one for each person, four copies for two, 12.

Multiply the above, 24*2* 12.

The second type: make full arrangements first: bind Party A and Party B together, and the total number is six! *2! = 1440

Then subtract the inconsistency: in the case of adjacent butyl groups, the butyl groups are bound together (Party A and Party B are still bound together): the quantity is.

5! *2! *2! (Party A and Party B exchange positions) =480

Then the total is: 1440-480=960.

Solutions like this. . . . . .