Let f (x) = a * x 2+b * x+c, so F(X)>-2X becomes a * x 2+(b+2) * x+c > 0, because the solution set of this inequality is (1 3), then a * x 2+.

1. the equation f (x)+6a = a * x 2+(2a-2) * x+3a = 0 has two equal roots, a.

2. Ask yourself this question! No bonus points, no motivation! It's troublesome to type these functions! Forgive me! joke ...