Fourth grade elementary school mathematics volume II talent curriculum unit quality evaluation three 70 pages additional questions.

Problem 2: Solution: Let the middle of these five natural numbers be X, and the rest be X- 1, X-2, X+ 1, X+2.

x+x+ 1+x+2+x- 1+(x- 1)+(x-2)= 465

5x=465

x=93

So: these five numbers are: 9 1, 92,

93,

94,

The first question is wrong.

There may be mistakes in the first topic "6 books and 7 books missing per person", but this topic is generally based on "9 books and 25 books missing per person, and 6 books and 25 books missing per person". This is a congruence problem. Find the least common multiple of 9 and 6, and then add the results of 25 to verify the third condition. If it doesn't work, multiply it by the least common multiple (starting from 2 times) and add the result of 25 to verify it until it meets.

The second question, because it is the last five consecutive natural numbers, as long as it is 465, you can add+1+2+3+4+5 after it, and the sum is 480.

Question 2: 1 plus 2 plus 3 plus 4 4= 10/0,465 465- 10 = 455455 divided by 5=9 1, 9 1 plus1= 92,92 plus/.

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