Point O is subjected to gravity mg, the supporting force F2 of the rod and the resultant force F of the pulling force between AO and rope BO, and the force is shown in the figure. According to the equilibrium conditions, the following results are obtained:
F = mgtan30 = 33mg mg
F2 = mgcos30 = 233mg mg.
F decomposition, as shown on the right. Let the tension on AO be F 1, because ∠ AOB = 60, there is
2F 1cos30 =F
Solution, F 1= 13mg.
So the answer is: 13mg, 233mg.