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How to deduce the summation formula of arithmetic sequence? What are the derivation methods?
Arithmetic progression is an important knowledge point in senior high school mathematics, and it is also a frequent test site in exams. The following is my "How to Derive Sum Formula of Arithmetic Sequence" for reference only. Welcome to read this article.

The derivation process of summation formula of arithmetic sequence;

Let the first term be a 1, the last term be an, the number of terms be n, the tolerance be d, and the sum of the first n terms be Sn, then sn = (a1+an) n/2; Sn = na1+n (n-1) d/2 (d is the tolerance)

When d≠0, Sn is a quadratic function of n, and (n, Sn) is a set of isolated points on the image of quadratic function. Using its geometric meaning, we can find the maximum value of the first n terms and Sn.

Note: Formulas 1, 2 and 3 are actually equivalent, and the tolerance in Formula 1 is not necessarily required to be equal to one.

It is proved by summation that Sn=a 1+a2+a3+. . . +an①

Sn=an+a(n- 1)+a(n-2)+.。 . +a 1②

①+②: 2sn = [a1+an]+[a2+a (n-1)]+[a3+a (n-2)]+...+[a1+an] (when n is even).

sn = {[a 1+an]+[a2+a(n- 1)]+[a3+a(n-2)]+...+[a 1+an]}/2

Sn=n(A 1+An)/2 (a 1, An, which can be expressed in the form of A 1+(N- 1) D, we can find that the numbers in brackets are all fixed values, that is, (a1+).

Extended reading: five basic formulas of geometric series

The general formula of (1) geometric series is:

An=A 1×q^(n- 1)

If the general formula is converted into an = a 1/q * q n (n ∈ n *), when q >;; 0, an can be regarded as a function of independent variable n, and point (n, an) is a set of isolated points on the curve y = a 1/q * q x.

(2) the relationship between any two am and an is an = am q (n-m).

(3) From the definition of geometric series, the general term formula and the first n terms formula, we can deduce that:

a 1 an = a2 an- 1 = a3 an-2 =…= AK an-k+ 1,k∈{ 1,2,…,n}

(4) Equal ratio mean term: AQAP = Ar 2, Ar is AP, and AQ is equal ratio mean term.

(5) Equal ratio summation: Sn = A 1+A2+A3+...+ Amp.

① when q≠ 1, sn = a1(1-q n)/(1-q) or sn = (a1-an× q) ÷ (/kloc)

② when q= 1, Sn=n×a 1(q= 1).

If π n = A 1 A2 … an, then π2n- 1=(an)2n- 1, π 2n+1= (an+1) 2n+1.