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Mathematical problems in the first semester of grade eight
Solution: 2n-65438+3 to the power of 0 = 3 to the power of 2n divided by 3; The n power of 9 = the 2n power of 3.

By: 2n- 1 to the 3rd power +N to the 9th power = 108.

Multiply both sides of the equation by 3:

2n power of 3+2n power of 3 * 3 =324

4*3 to the 2n power =324.

The 2n power of 3 = 81= 3 power of 4.

2n=4

n=2

(2n-2) to the nth power =(4-2)? =4