Make the left directrix of this ellipse, intersection points A and B are perpendicular to the left directrix, vertical feet are D and E respectively, intersection point B is perpendicular to AD, vertical feet are H, and intersect with X axis at point M, let AF 1=3t, then AF2=t, F 1F2=2c=2√2t, that is, c=√2t.

(1) n = 1, which is simple;

(2) The following proves that m=5:

With the above preparations, this problem can be solved. For convenience, let BF 1=x and use the proportional line segment, we get: BF 1:BA=MF 1:AH, where BF 1 = x, BA=x+3t, MF1= c-. Complete the certificate.