So μ= 1 15, σ 2 = 25, σ=5.

According to the "attachment" in the title

p( 1 15-3 * 5 & lt； X & lt 1 15+3*5)=0.9974

P ( 100

According to the normal distribution, the image is symmetrical about X=μ( 1 15).

So p (x > = 130)=( 1-0.9974)/2=0.00 13

Do you understand ~ ~