(1) Let x= 1.

(2- 1)? = a5+a4+a3+a2+a 1+A0 = 1

therefore

A0+a 1+a2+a3+a4+a5 = 1

(2) Let x=- 1.

(-2- 1)? =-a5+a4-a3+a2-a 1+a0=9

therefore

a0-a 1+a2-a3+a4-a5=9

(3) Derived from (1) and (2)

A0+a 1+a2+a3+a4+a5 = 1

a0-a 1+a2-a3+a4-a5=9

amount to

2a0+2a2+2a4= 10

a0+a2+a4=5