The ratio of the areas of two concentric circles is the square of the diameter ratio.

So the area ratio = 23 2/17 2.

The volume of the whole pipeline = Pa R 2 = Pa (23/2) 2x 1000 cubic millimeter.

Volume of solid part = pi [(23/2) 2-(17/2) 2] x1000 cubic millimeter.

Volume of hollow part = pai x (17/2) 2x1000 cubic millimeter.

Pipeline density =1.56/{pi [23/2] 2-(17/2) 2]}100000x1The final unit is KG/m3.

The calculation result is

The volume of the whole tube =4 15265 cubic millimeter.

Volume of solid part = 188400 m3.

The volume of the hollow part =226865 cubic millimeters.

Density of the pipe = 8280.255 kg/m3.