(1) Because the angle ABC = 90, D can't be on the right side of point C, so B is BD vertical AB.

The x axis intersects with point d, so point d is the point to be found at this time. Because the coordinates of A and C are (-3,0) (10), AC=4. Because BC/AC=3/4 and BC=3, AB=5 AD=25/4.

Because the angle ACB = ABD = 90°, so AC * CD = BC 2, so CD=9/4, so D (13/4,0).

(2) Two cases: when the angle APQ=ABD = 90°, that is, PQ is parallel to BD, because angle A= Angle A, angle APQ = ABD, and triangle APQ is similar to ABD, so AP:AB=AQ:AD.

That is, m: 5 = 25/4-m: 25/4 gives m=25/9.

When the angle AQP = ABD = 90°, the triangle AQP is similar to ABD because angle A= angle A.

So AQ:AB=AP:AD is 25/4-M: 5 = M: 25/4, and the solution is m= 125/36.

So when m=25/9 or 125/36, there is similarity.