Analysis: In the triangle ABC
∵ AB = BC, ∴⊿ABC is an isosceles triangle.
∵M is the midpoint of BC, and AM is the bisector of angle BAC.
According to the nature of the bisector of the inner angle, AC/AB=CM/MB= 1.
∴⊿ABC is an equilateral triangle
Let its side length be a.
∴ Vector AB Vector BC=| Vector AB|? Vector BC | cos60 = a 2/2