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20 1 1 Liaoning Dandong Mathematics 16.
16, known: As shown in the figure, DE is the center line of △ABC, point P is the midpoint of DE, and the extension line of CP intersects with AB at point Q, then S △ DPQ: S △ ABC =

Solution: ∫DE is the center line, and P is the midpoint of DE.

∴2de=bc; 4DP=2DE=AB,S△ADE:S△ABC= 1:4,

∫DE∨BC,

∴△DPQ∽△BCQ,

∴4QD=QB,

∫D is the midpoint of AB,

∴2QD=QA,

∴S△DPQ:S△APQ= 1:2,

∫S△APD = S△APE,

∴S△DPQ:S△ADE= 1:6,

∴S△DPQ:S△ABC= 1:24.