16, known: As shown in the figure, DE is the center line of △ABC, point P is the midpoint of DE, and the extension line of CP intersects with AB at point Q, then S △ DPQ: S △ ABC =

Solution: ∫DE is the center line, and P is the midpoint of DE.

∴2de=bc； 4DP=2DE=AB，S△ADE:S△ABC= 1:4，

∫DE∨BC，

∴△DPQ∽△BCQ，

∴4QD=QB，

∫D is the midpoint of AB,

∴2QD=QA，

∴S△DPQ:S△APQ= 1:2，

∫S△APD = S△APE，

∴S△DPQ:S△ADE= 1:6，

∴S△DPQ:S△ABC= 1:24.