Solution: ∫DE is the center line, and P is the midpoint of DE.
∴2de=bc; 4DP=2DE=AB,S△ADE:S△ABC= 1:4,
∫DE∨BC,
∴△DPQ∽△BCQ,
∴4QD=QB,
∫D is the midpoint of AB,
∴2QD=QA,
∴S△DPQ:S△APQ= 1:2,
∫S△APD = S△APE,
∴S△DPQ:S△ADE= 1:6,
∴S△DPQ:S△ABC= 1:24.