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Basic problems in solving equations in the first class of mathematics in the fifth grade of primary school
Last question: Because the total time for dogs to walk is actually the time when A and B meet, because dogs start at the same time, and A and B stop at the same time when they meet later, so the time is the same. Therefore, the meeting time of A and B is =100 ÷ (6+4) =10x65438+the distance of the dog.