Analysis: Make the perpendicular line of AB, and then answer according to the properties of equilateral triangle and congruent triangles.

Solution: the middle vertical line is AB,

∫△ABC is an equilateral triangle, △ABD is an isosceles triangle;

∴AB's middle vertical line must pass through C and D, ∠ BCE = 30;

AB = BP = BC，∠DBP=∠DBC，BD = BD

∴△BDC≌△BDP, so ∠ BPD = 30.

Therefore, the degree of ∠BPD is 30.

Note: This question is not difficult. The key to solve this problem is to make auxiliary lines and then use the properties of equilateral triangles to solve it.

Numerous teams will answer your questions and hope to adopt O(∩_∩)O~