There are two intersections between the two equations, namely B2-4ac > 0, (a2 should appear after sorting, so I'm afraid of trouble, so I set the reduction method to t and solve a2. You should know that E = C/A = C2/A2 = (A2+B2)/A2 =1+(B/A) 2 under the radical sign.

I also know that b= 1. So I removed a range. Because the hyperbola itself e > 1. So take the intersection.

2. Directly using the vector method, the corresponding coefficients are equal. The intersection point p with the Y axis is (0, 1), and finally it is brought into the linear equation. It is enough to get one of the two points. Then substitute it into hyperbolic equation. This question has come out.