If the inequality f (x) >; The solution set of 0 is (1, positive infinity),

Then g (x) = ax-bx >; 1 applies to any X (1, positive infinity).

And because of a>1> b & gt0,

So y = a x is increasing function and y = b x is a subtraction function.

So g (x) = a x-b x is increasing function.

So g (x) gt; g( 1)=a-b，x & gt 1.

If a-b >; 1, that is, a & gtb+ 1,

Then g (x) > a-b >: For any x belonging to (1, positive infinity), 1 is true.

So choose (c)

= = = = = = = = =

It's a little confusing

It's just a multiple-choice question. Think algebra.

a=2，b= 1/2。

g(x)=2^x-( 1/2)^x.

Then g (1) = 3/2 >; 1

g(2)= 4- 1/4 & gt； 1,

g(3)= 8- 1/8 & gt； 1.

...

Meet the conditions.

And 2> 1/2+1,

So choose C.

G (x) = a x-b x is not so easy to draw!

Why not draw y = a x and y = b x at the same time and compare the two curves under the same x,

"distance" of y