Simplifying A2 (x-1) > B2 (1+x)+2ab gives:
a^2x- b^2 x & gt； a^2 +b^2+2ab
(a 2-b 2) x > (a+b) 2, because both a and b belong to R+,
∴ further changed to: (a-b) x > a+b
(1) if a=b, then 0 > a+b, no solution!
② if a > b, then x > (a+b)/(a-b);
③ if a < b, then x < (a+b)/(a-b).