The solution is,

The analytical formula of parabola is y.

=-X-4；

(2) Point (X) where point P moves

，0)，BP2

=

BD？

BC,

Jean x

=

0，y

=

-4,

C(0, -4) of the point coordinates.

∫PD∑AC，

∴△BPD∽△BAC，

∴。

B.C.

=,

ab blood type

=

6、BP

=

x-(-2)= 1

x

+2。

∴BD

===。 about

* BP2

=

Bachelor of science

B.C.

∴(x

+2)2

=

Solution, X 1

=

X2

=

-2(-2 unqualified questions, rounded),

∴ The coordinate of point P is (0), that is, when point P (0) moves, BP2

=

BD？

BC;

(3) BPD∽△BAC，

Yes

∴×

And BPC of S△

=

X(X

+2)*

four

-

When x

=

At 1, the maximum value of S△BPC is 3. about

That is, the coordinates of point P (1, 0) and the delta △PDC area.