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Three math problems in the middle
7.x-3=0 x=3 (the number in the middle of the radical sign is greater than or equal to zero)

Y- 1=0 y= 1 (absolute value is greater than or equal to zero)

Z+2=0 z=-2 (square number is greater than or equal to zero)

These three use the nonnegativity of root sign, absolute value and square number. The sum of three non-negative numbers is zero, and each is equal to zero.

8.2a- 1= 1^2 2a- 1 = 1 a = 1

b- 1=( 2)^2 b- 1=4 b=5

4 2 > 13 > 3 2 4 > radical sign 13 > 3 So the integer part is 3, which means c=3.

When a = 1, b = 5, and c = 3, the original formula = 1- 10+9=0.

So the square root of a-2b+c 2 is 0.

9, x-3=3-x x=3 because the root sign is non-negative.

When x=3, the original formula y=0+0+8=8.

When x = 3 and y = 8, the root number (x+y)= root number 1 1.

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