The first one is that two cars met 47 kilometers apart.

(432-47) divided by (40+54)=385 divided by 94=4 and 9/94 (hours).

In the second case, two cars meet, 47 kilometers apart.

(432+47) divided by (40+54)=489 divided by 94=5 and 29 (hours) of 94.

2、

72 divided by 2 equals 36. . Armor speed

5 16-36*(6+2)=228。 . . Driving distance of b car

228 divided by 6=38 (km/h). . . B car speed

3、

The speed difference between the two cars is 60-55=5.

The time when two cars meet is 20 divided by 5=4.

Distance between the two places (60+55)*4=460 (km)

4、

When they first met, A and B * * * walked the whole way. At this time, A walked 700 meters (from A).

When we met for the second time, A and B * * * walked twice. Of course, it's been two times since we first met, so A should go.

700*2= 1400 meters. At this time, A should have walked a full distance of +400 meters from B.

Then the whole journey is1400-400 =1000 m.

Because they are all application questions: I won't help you write anything. You can ask me if you don't understand. I wish you progress in your study:)