|b|=2k= 1,k= 1/2。
So b = (1, 0)
(2) b=(x, y)
a b = 2x = | a | | b | cos 120 = 2× 1×(- 1/2)=- 1
x=- 1/2
|b|? =x? +y? = 1,y =∞3/2。
B = (- 1/2, ∨3/2) or B = (- 1/2, -∨ 3/2).
A+B = (3/2, ∞3/2) or (3/2, -3/2).